2[9-3(-2x-4)]=12x+42

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Solution for 2[9-3(-2x-4)]=12x+42 equation:


Simplifying
2[9 + -3(-2x + -4)] = 12x + 42

Reorder the terms:
2[9 + -3(-4 + -2x)] = 12x + 42
2[9 + (-4 * -3 + -2x * -3)] = 12x + 42
2[9 + (12 + 6x)] = 12x + 42

Combine like terms: 9 + 12 = 21
2[21 + 6x] = 12x + 42
[21 * 2 + 6x * 2] = 12x + 42
[42 + 12x] = 12x + 42

Reorder the terms:
42 + 12x = 42 + 12x

Add '-42' to each side of the equation.
42 + -42 + 12x = 42 + -42 + 12x

Combine like terms: 42 + -42 = 0
0 + 12x = 42 + -42 + 12x
12x = 42 + -42 + 12x

Combine like terms: 42 + -42 = 0
12x = 0 + 12x
12x = 12x

Add '-12x' to each side of the equation.
12x + -12x = 12x + -12x

Combine like terms: 12x + -12x = 0
0 = 12x + -12x

Combine like terms: 12x + -12x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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